How many moles of O2(g) are needed to produce 100.0 moles of 2Al2O3(s) in the reaction 4Al(s) + 3O2(g) → 2Al2O3(s)?

To determine how many moles of O2 are needed to produce 100.0 moles of Al2O3, we can analyze the balanced chemical equation:

4Al(s) + 3O2(g) → 2Al2O3(s).

This equation shows that for every 2 moles of Al2O3 produced, 3 moles of O2 are required.

To find the amount of O2 needed for 100.0 moles of Al2O3, we can set up a ratio based on the coefficients from the balanced equation:

• For every 2 moles of Al2O3, 3 moles of O2 are needed.

To find out how many moles of O2 are needed for 100.0 moles of Al2O3, we can set up a proportion:

(3 moles O2) / (2 moles Al2O3) = x moles O2 / (100.0 moles Al2O3).

Solving for x, we cross-multiply and obtain:

x = (3 moles O2 / 2 moles Al2O3) * 100.0 moles Al2O3 =